c programming examples #1

               c programming examples

C programming examples :- These programs illustrate various programming elements, concepts such as using operators, loops, functions, single and double dimensional arrays, performing operations on strings, files, pointers etc. Browse the code from simple c program to complicated ones you are looking for, every one of them is provided with output. C program download with executable files, so that you save on your computer and run programs without compiling the source code. All programs are made using c programming language and Codeblocks, most of these will work under Dev c++ compiler also. Download software you need to develop codes. The first program prints "Hello World" on screen.

  ##c hello world program

C hello world program :- c programming language code to print hello world. This program prints hello world, printf function is used to display text on screen, '\n' places cursor on the beginning of next line, stdio.h header file contains declaration of printf function. The code will work on all operating systems may be it's Linux, Mac or any other and compilers. To learn a programming language you must start writing programs in it and may be your first c code while learning programming.

C hello world example

#include <stdio.h>
 
int main()
{
  printf("Hello world\n");
  return 0;
}

Hello world program in c

We may store "hello world" in a character array and then print it.

#include <stdio.h>
 
int main()
{
  char string[] = "Hello World";
 
  printf("%s\n", string);
 
  return 0;
}

Output of program:

 ##c program print integer

This c program first inputs an integer and then prints it. Input is done using scanf function and number is printed on screen using printf.

C programming code

#include <stdio.h>
 
int main()
{
  int a;
 
  printf("Enter an integer\n");
  scanf("%d", &a);
 
  printf("Integer that you have entered is %d\n", a);
 
  return 0;
}

Output of program:

##c program to add two numbers

C program to add two numbers: This c language program perform the basic arithmetic operation of addition on two numbers and then prints the sum on the screen. For example if the user entered two numbers as 5, 6 then 11 ( 5 + 6 ) will be printed on the screen.

C programming code

#include<stdio.h>
 
main()
{
   int a, b, c;
 
   printf("Enter two numbers to add\n");
   scanf("%d%d",&a,&b);
 
   c = a + b;
 
   printf("Sum of entered numbers = %d\n",c);
 
   return 0;
}

Add numbers program executable.

Output of program

 ##C program to perform addition, subtraction, multiplication and division

C program to perform basic arithmetic operations i.e. addition , subtraction, multiplication and division of two numbers. Numbers are assumed to be integers and will be entered by the user.

C programming code

#include <stdio.h>
 
int main()
{
   int first, second, add, subtract, multiply;
   float divide;
 
   printf("Enter two integers\n");
   scanf("%d%d", &first, &second);
 
   add      = first + second;
   subtract = first - second;
   multiply = first * second;
   divide   = first / (float)second;   //typecasting
 
   printf("Sum = %d\n",add);
   printf("Difference = %d\n",subtract);
   printf("Multiplication = %d\n",multiply);
   printf("Division = %.2f\n",divide);
 
   return 0;
}

In c language when we divide two integers we get integer result for example 5/2 evaluates to 2. As a general rule integer/integer = integer and float/integer = float or integer/float = float. So we convert denominator to float in our program, you may also write float in numerator. This explicit conversion is known as typecasting.
Arithmetic operations.
Output of program:

 ## c program to check odd or even

c program to check odd or even: We will determine whether a number is odd or even by using different methods all are provided with a code in c language. As you have study in mathematics that in decimal number system even numbers are divisible by 2 while odd are not so we may use modulus operator(%) which returns remainder, For example 4%3 gives 1 ( remainder when four is divided by three). Even numbers are of the form 2*p and odd are of the form (2*p+1) where p is is an integer.
We can use bitwise AND (&) operator to check odd or even, as an example consider binary of 7 (0111) when we perform 7 & 1 the result will be one and you may observe that the least significant bit of every odd number is 1, so ( odd_number & 1 ) will be one always and also ( even_number & 1 ) is zero.
In c programming language when we divide two integers we get an integer result, For example the result of 7/3 will be 2.So we can take advantage of this and may use it to find whether the number is odd or even. Consider an integer n we can first divide by 2 and then multiply it by 2 if the result is the original number then the number is even otherwise the number is odd. For example 11/2 = 5, 5*2 = 10 ( which is not equal to eleven), now consider 12/2 = 6 and 6 *2 = 12 ( same as original number). These are some logic which may help you in finding if a number is odd or not.

>C program to check odd or even using modulus operator

#include<stdio.h>
 
main()
{
   int n;
 
   printf("Enter an integer\n");
   scanf("%d",&n);
 
   if ( n%2 == 0 )
      printf("Even\n");
   else
      printf("Odd\n");
 
   return 0;
}

>C program to check odd or even using bitwise operator

#include<stdio.h>
 
main()
{
   int n;
 
   printf("Enter an integer\n");
   scanf("%d",&n);
 
   if ( n & 1 == 1 )
      printf("Odd\n");
   else
      printf("Even\n");
 
   return 0;
}

>C program to check odd or even without using bitwise or modulus operator

#include<stdio.h>
 
main()
{
   int n;
 
   printf("Enter an integer\n");
   scanf("%d",&n);
 
   if ( (n/2)*2 == n )
      printf("Even\n");
   else
      printf("Odd\n");
 
   return 0;
}

>Find odd or even using conditional operator

#include<stdio.h>
 
main()
{
   int n;
 
   printf("Enter an integer\n");
   scanf("%d",&n);
 
   n%2 == 0 ? printf("Even number\n") : printf("Odd number\n");
 
   return 0;
}

 ##c program to check whether input alphabet is a vowel or not        





This code checks whether an input alphabet is a vowel or not. Both lower-case and upper-case are checked.






C programming code

#include <stdio.h>
 
main()
{
  char ch;
 
  printf("Enter a character\n");
  scanf("%c", &ch);
 
  if (ch == 'a' || ch == 'A' || ch == 'e' || ch == 'E' || ch == 'i' || ch == 'I' || ch =='o' || ch=='O' || ch == 'u' || ch == 'U')
    printf("%c is a vowel.\n", ch);
  else
    printf("%c is not a vowel.\n", ch);
 
  return 0;
}

Output:




Check vowel using switch statement

#include <stdio.h>
 
main()
{
  char ch;
 
  printf("Enter a character\n");
  scanf("%c", &ch);
 
  switch(ch)
  {
    case 'a':
    case 'A':
    case 'e':
    case 'E':
    case 'i':
    case 'I':
    case 'o':
    case 'O':
    case 'u':
    case 'U':
      printf("%c is a vowel.\n", ch);
      break;
    default:
      printf("%c is not a vowel.\n", ch);
  }              
 
  return 0;
}



Function to check vowel

int check_vowel(char a)
{
    if (a >= 'A' && a <= 'Z')
       a = a + 'a' - 'A';   /* Converting to lower case or use a = a + 32 */
 
    if (a == 'a' || a == 'e' || a == 'i' || a == 'o' || a == 'u')
       return 1;
 
    return 0;
}






 ##c program to check leap year  








c program to check leap year: c code to check leap year, year will be entered by the user. Please read the leap year article before reading the code, it will help you to understand the program.



C programming code

#include <stdio.h>
 
int main()
{
  int year;
 
  printf("Enter a year to check if it is a leap year\n");
  scanf("%d", &year);
 
  if ( year%400 == 0)
    printf("%d is a leap year.\n", year);
  else if ( year%100 == 0)
    printf("%d is not a leap year.\n", year);
  else if ( year%4 == 0 )
    printf("%d is a leap year.\n", year);
  else
    printf("%d is not a leap year.\n", year);  
 
  return 0;
}






Compiler used: 


GCC




Output of program: 













         ## add digits of number in c     








C
 program to add digits of a number: Here we are using modulus 
operator(%) to extract individual digits of number and adding them. 



C programming code

#include <stdio.h>
 
main()
{
   int n, sum = 0, remainder;
 
   printf("Enter an integer\n");
   scanf("%d",&n);
 
   while(n != 0)
   {
      remainder = n % 10;
      sum = sum + remainder;
      n = n / 10;
   }
 
   printf("Sum of digits of entered number = %d\n",sum);
 
   return 0;
}

For example if the input is 98, sum(variable) is 0 initially

98%10 = 8 (% is modulus operator which gives us remainder when 98 is divided by 10).

sum = sum + remainder

so sum = 8 now.

98/10 = 9 because in c whenever we divide integer by another integer we get an integer.

9%10 = 9

sum = 8(previous value) + 9

sum = 17

9/10 = 0.

So finally n = 0, loop ends we get the required sum.

Output of program:









          Factorial program in c        








Factorial
 program in c: c code to find and print factorial of a number, three 
methods are given, first one uses a for loop, second uses a function to find factorial and third using recursion. Factorial is represented using !, so five factorial will be written as 5!, n factorial as n!. Also

n! = n*(n-1)*(n-2)*(n-3)...3.2.1 and zero factorial is defined as one i.e. 0!=1.



Factorial program in c using for loop
: Here we find factorial using for loop.


#include <stdio.h>
 
int main()
{
  int c, n, fact = 1;
 
  printf("Enter a number to calculate it's factorial\n");
  scanf("%d", &n);
 
  for (c = 1; c <= n; c++)
    fact = fact * c;
 
  printf("Factorial of %d = %d\n", n, fact);
 
  return 0;
}

Factorial program in c using function


#include <stdio.h>
 
long factorial(int);
 
int main()
{
  int number;
  long fact = 1;
 
  printf("Enter a number to calculate it's factorial\n");
  scanf("%d", &number);
 
  printf("%d! = %ld\n", number, factorial(number));
 
  return 0;
}
 
long factorial(int n)
{
  int c;
  long result = 1;
 
  for (c = 1; c <= n; c++)
    result = result * c;
 
  return result;
}



Factorial program in c using recursion

#include<stdio.h>
 
long factorial(int);
 
int main()
{
  int num;
  long f;
 
  printf("Enter a number to find factorial\n");
  scanf("%d", &num); 
 
  if (num < 0)
    printf("Negative numbers are not allowed.\n");
  else
  {
    f = factorial(num);
    printf("%d! = %ld\n", num, f);
  }
 
  return 0;
}
 
long factorial(int n)
{
  if (n == 0)
    return 1;
  else
    return(n * factorial(n-1));
}





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